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C语言程序设计经典实例之十

王朝c/c++·作者佚名  2006-01-06
窄屏简体版  字體: |||超大  

【程序91】

题目:时间函数举例1

1.程序分析:

2.程序源代码:

#include "stdio.h"

#include "time.h"

void main()

{

time_t lt; /*define a longint time varible*/

lt=time(NULL);/*system time and date*/

PRintf(ctime(<)); /*english format output*/

printf(asctime(localtime(<)));/*tranfer to tm*/

printf(asctime(gmtime(<))); /*tranfer to Greenwich time*/

}

【程序92】

题目:时间函数举例2

1.程序分析:

2.程序源代码:

/*calculate time*/

#include "time.h"

#include "stdio.h"

main()

{

time_t start,end;

int i;

start=time(NULL);

for(i=0;i<3000;i++)

{

printf("\1\1\1\1\1\1\1\1\1\1\n");

}

end=time(NULL);

printf("\1: The different is %6.3f\n",difftime(end,start));

}

【程序93】

题目:时间函数举例3

1.程序分析:

2.程序源代码:

/*calculate time*/

#include "time.h"

#include "stdio.h"

main()

{

clock_t start,end;

int i;

double var;

start=clock();

for(i=0;i<10000;i++)

{

printf("\1\1\1\1\1\1\1\1\1\1\n");

}

end=clock();

printf("\1: The different is %6.3f\n",(double)(end-start));

}

【程序94】

题目:时间函数举例4,一个猜数游戏,判定一个人反应快慢。(版主初学时编的)

1.程序分析:

2.程序源代码:

#include "time.h"

#include "stdlib.h"

#include "stdio.h"

main()

{

char c;

clock_t start,end;

time_t a,b;

double var;

int i,guess;

srand(time(NULL));

printf("do you want to play it.('y' or 'n') \n");

loop:

while((c=getchar())=='y')

{

i=rand()%100;

printf("\nplease input number you guess:\n");

start=clock();

a=time(NULL);

scanf("%d",&guess);

while(guess!=i)

{

if(guess>i)

{

printf("please input a little smaller.\n");

scanf("%d",&guess);

}

else

{

printf("please input a little bigger.\n");

scanf("%d",&guess);

}

}

end=clock();

b=time(NULL);

printf("\1: It took you %6.3f seconds\n",var=(double)(end-start)/18.2);

printf("\1: it took you %6.3f seconds\n\n",difftime(b,a));

if(var<15)

printf("\1\1 You are very clever! \1\1\n\n");

else if(var<25)

printf("\1\1 you are normal! \1\1\n\n");

else

printf("\1\1 you are stupid! \1\1\n\n");

printf("\1\1 Congradulations \1\1\n\n");

printf("The number you guess is %d",i);

}

printf("\ndo you want to try it again?(\"yy\".or.\"n\")\n");

if((c=getch())=='y')

goto loop;

}

更多内容请看C/C++进阶技术文档专题,或

【程序95】

题目:家庭财务治理小程序

1.程序分析:

2.程序源代码:

/*money management system*/

#include "stdio.h"

#include "dos.h"

main()

{

FILE *fp;

strUCt date d;

float sum,chm=0.0;

int len,i,j=0;

int c;

char ch[4]="",ch1[16]="",chtime[12]="",chshop[16],chmoney[8];

pp: clrscr();

sum=0.0;

gotoxy(1,1);printf("----------------------------------------------------");

gotoxy(1,2);printf(" money management system(C1.0) 2000.03 ");

gotoxy(1,3);printf("----------------------------------------------------");

gotoxy(1,4);printf(" -- money records -- -- today cost list -- ");

gotoxy(1,5);printf(" ------------------------ -----------------------------");

gotoxy(1,6);printf(" date: -------------- ");

gotoxy(1,7);printf(" ");

gotoxy(1,8);printf(" -------------- ");

gotoxy(1,9);printf(" thgs: ------------------ ");

gotoxy(1,10);printf(" ");

gotoxy(1,11);printf(" ------------------ ");

gotoxy(1,12);printf(" cost: ---------- ");

gotoxy(1,13);printf(" ");

gotoxy(1,14);printf(" ---------- ");

gotoxy(1,15);printf(" ");

gotoxy(1,16);printf(" ");

gotoxy(1,17);printf(" ");

gotoxy(1,18);printf(" ");

gotoxy(1,19);printf(" ");

gotoxy(1,20);printf(" ");

gotoxy(1,21);printf(" ");

gotoxy(1,22);printf(" ");

gotoxy(1,23);printf("--------------------------------------------------");

i=0;

getdate(&d);

sprintf(chtime,"%4d.%02d.%02d",d.da_year,d.da_mon,d.da_day);

for(;;)

{

gotoxy(3,24);printf(" Tab __browse cost list Esc __quit");

gotoxy(13,10);printf(" ");

gotoxy(13,13);printf(" ");

gotoxy(13,7);printf("%s",chtime);

j=18;

ch[0]=getch();

if(ch[0]==27)

break;

strcpy(chshop,"");

strcpy(chmoney,"");

if(ch[0]==9)

{

mm:i=0;

fp=fopen("home.dat","r+");

gotoxy(3,24);printf(" ");

gotoxy(6,4);printf(" list records ");

gotoxy(1,5);printf("-------------------------------------");

gotoxy(41,4);printf(" ");

gotoxy(41,5);printf(" ");

while(fscanf(fp,"%10s%14s%f\n",chtime,chshop,&chm)!=EOF)

{

if(i==36)

{

getch();

i=0;

}

if ((i%36)<17)

{

gotoxy(4,6+i);

printf(" ");

gotoxy(4,6+i);

}

else

if((i%36)>16)

{

gotoxy(41,4+i-17);

printf(" ");

gotoxy(42,4+i-17);

}

i++;

sum=sum+chm;

printf("%10s %-14s %6.1f\n",chtime,chshop,chm);}

gotoxy(1,23);printf("----------------------------------------------");

gotoxy(1,24);printf(" ");

gotoxy(1,25);printf("----------------------------------------------");

gotoxy(10,24);printf("total is %8.1f$",sum);

fclose(fp);

gotoxy(49,24);printf("press any key to.....");getch();goto pp;

}

else

{

while(ch[0]!='\r')

{

if(j<10)

{

strncat(chtime,ch,1);

j++;

}

if(ch[0]==8)

{

len=strlen(chtime)-1;

if(j>15)

{

len=len+1;

j=11;

}

strcpy(ch1,"");

j=j-2;

strncat(ch1,chtime,len);

strcpy(chtime,"");

strncat(chtime,ch1,len-1);

gotoxy(13,7);printf(" ");

}

gotoxy(13,7);printf("%s",chtime);ch[0]=getch();

if(ch[0]==9)

goto mm;

if(ch[0]==27)

exit(1);

}

gotoxy(3,24);printf(" ");

gotoxy(13,10);

j=0;

ch[0]=getch();

while(ch[0]!='\r')

{

if (j<14)

{

strncat(chshop,ch,1);

j++;

}

if(ch[0]==8)

{

len=strlen(chshop)-1;

strcpy(ch1,"");

j=j-2;

strncat(ch1,chshop,len);

strcpy(chshop,"");

strncat(chshop,ch1,len-1);

gotoxy(13,10);printf(" ");

}

gotoxy(13,10);printf("%s",chshop);ch[0]=getch();}

gotoxy(13,13);

j=0;

ch[0]=getch();

while(ch[0]!='\r')

{

if (j<6)

{

strncat(chmoney,ch,1);

j++;

}

if(ch[0]==8)

{

len=strlen(chmoney)-1;

strcpy(ch1,"");

j=j-2;

strncat(ch1,chmoney,len);

strcpy(chmoney,"");

strncat(chmoney,ch1,len-1);

gotoxy(13,13);printf(" ");

}

gotoxy(13,13);printf("%s",chmoney);ch[0]=getch();

}

if((strlen(chshop)==0)(strlen(chmoney)==0))

continue;

if((fp=fopen("home.dat","a+"))!=NULL);

fprintf(fp,"%10s%14s%6s",chtime,chshop,chmoney);

fputc('\n',fp);

fclose(fp);

i++;

gotoxy(41,5+i);

printf("%10s %-14s %-6s",chtime,chshop,chmoney);

}

}

}

【程序96】

题目:计算字符串中子串出现的次数

1.程序分析:

2.程序源代码:

#include "string.h"

#include "stdio.h"

main()

{

char str1[20],str2[20],*p1,*p2;

int sum=0;

printf("please input two strings\n");

scanf("%s%s",str1,str2);

p1=str1;p2=str2;

while(*p1!='\0')

{

if(*p1==*p2)

{

while(*p1==*p2&&*p2!='\0')

{

p1++;

p2++;

}

}

else

p1++;

if(*p2=='\0')

sum++;

p2=str2;

}

printf("%d",sum);

getch();

}

【程序97】

题目:从键盘输入一些字符,逐个把它们送到磁盘上去,直到输入一个#为止。

1.程序分析:

2.程序源代码:

#include "stdio.h"

main()

{

FILE *fp;

char ch,filename[10];

scanf("%s",filename);

if((fp=fopen(filename,"w"))==NULL)

{

printf("cannot open file\n");

exit(0);

}

ch=getchar();

ch=getchar();

while(ch!='#')

{

fputc(ch,fp);putchar(ch);

ch=getchar();

}

fclose(fp);

}

更多内容请看C/C++进阶技术文档专题,或

【程序98】

题目:从键盘输入一个字符串,将小写字母全部转换成大写字母,然后输出到一个磁盘文件“test”中保存。输入的字符串以!结束。

1.程序分析:

2.程序源代码:

#include "stdio.h"

main()

{

FILE *fp;

char str[100],filename[10];

int i=0;

if((fp=fopen("test","w"))==NULL)

{

printf("cannot open the file\n");

exit(0);

}

printf("please input a string:\n");

gets(str);

while(str[i]!='!')

{

if(str[i]>='a'&&str[i]<='z')

str[i]=str[i]-32;

fputc(str[i],fp);

i++;

}

fclose(fp);

fp=fopen("test","r");

fgets(str,strlen(str)+1,fp);

printf("%s\n",str);

fclose(fp);

}

【程序99】

题目:有两个磁盘文件A和B,各存放一行字母,要求把这两个文件中的信息合并(按字母顺序排列),

输出到一个新文件C中。

1.程序分析:

2.程序源代码:

#include "stdio.h"

main()

{

FILE *fp;

int i,j,n,ni;

char c[160],t,ch;

if((fp=fopen("A","r"))==NULL)

{

printf("file A cannot be opened\n");

exit(0);

}

printf("\n A contents are :\n");

for(i=0;(ch=fgetc(fp))!=EOF;i++)

{

c[i]=ch;

putchar(c[i]);

}

fclose(fp);

ni=i;

if((fp=fopen("B","r"))==NULL)

{

printf("file B cannot be opened\n");

exit(0);

}

printf("\n B contents are :\n");

for(i=0;(ch=fgetc(fp))!=EOF;i++)

{

c[i]=ch;

putchar(c[i]);

}

fclose(fp);

n=i;

for(i=0;i<n;i++)

for(j=i+1;j<n;j++)

if(c[i]>c[j])

{

t=c[i];c[i]=c[j];c[j]=t;

}

printf("\n C file is:\n");

fp=fopen("C","w");

for(i=0;i<n;i++)

{

putc(c[i],fp);

putchar(c[i]);

}

fclose(fp);

}

【程序100】

题目:有五个学生,每个学生有3门课的成绩,从键盘输入以上数据(包括学生号,姓名,三门课成绩),计算出平均成绩,况原有的数据和计算出的平均分数存放在磁盘文件"stud"中。

1.程序分析:

2.程序源代码:

#include "stdio.h"

struct student

{

char num[6];

char name[8];

int score[3];

float avr;

} stu[5];

main()

{

int i,j,sum;

FILE *fp;

/*input*/

for(i=0;i<5;i++)

{

printf("\n please input No. %d score:\n",i);

printf("stuNo:");

scanf("%s",stu[i].num);

printf("name:");

scanf("%s",stu[i].name);

sum=0;

for(j=0;j<3;j++)

{

printf("score %d.",j+1);

scanf("%d",&stu[i].score[j]);

sum+=stu[i].score[j];

}

stu[i].avr=sum/3.0;

}

fp=fopen("stud","w");

for(i=0;i<5;i++)

if(fwrite(&stu[i],sizeof(struct student),1,fp)!=1)

printf("file write error\n");

fclose(fp);

}

更多内容请看C/C++进阶技术文档专题,或

 
 
 
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