PHP5对Mysql5的任意数据库表的管理代码示例(三)

王朝mysql·作者佚名  2008-05-31
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续:点击编辑一个条目会跳转至edit.php

//edit.php

<html>

<head><title>Editing an entry from the database</title>

<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />

</head>

<body bgcolor=#ffffff>

<h2>Edit an entry</h2>

<?

$database = "sunsite";

$tablename = $_REQUEST['tablename'];

echo "<h2>Data from $tablename</h2>";

mysql_connect("localhost","root","") or die ("Problem connecting to DataBase");

$query = "show columns from $tablename";

$result = mysql_db_query($database,$query);

$column = 0;

if ($result)

{

echo "Found these entries in the database:<br><p></p>";

echo "<table width=90% align=center border=1><tr>";

while ($r = mysql_fetch_array($result))

{

echo "<td align=center bgcolor=#00FFFF>$r[0]</td>";

$colname[$column] = $r[0];

$column = $column + 1;

}

echo "</tr>";

mysql_free_result($result);

$query = "select * from $tablename";

$result = mysql_db_query($database, $query);

if ($result)

while ($r = mysql_fetch_array($result))

{

echo "<tr>";

echo "<td><a href="editing.php?$colname[0]=$r[0]&tablename=$tablename">$r[0]</td>";

for($col=1;$col<$column;$col++) echo "<td>$r[$col]</td>";

echo "</tr>";

}

echo "</table>";

}

else echo "No data.";

mysql_free_result($result);

?>

<a href="tables.php?tablename=<? echo "$tablename"?>">Finish</a>

</body>

</html>

然后选择其中一个id,会跳出具体的内容并要求用户修改。

//editing.php

<html>

<head><title>Editing an entry</title>

<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />

</head>

<body bgcolor=#ffffff>

<h1>Editing an entry</h1>

<?

$database = "sunsite";

$tablename = $_GET['tablename'];

mysql_connect("localhost","root","") or die ("Problem connecting to DataBase");

$query = "show columns from $tablename";

$result = mysql_db_query($database,$query);

$column = 0;

if ($result)

{

while ($r = mysql_fetch_array($result))

{

$colname[$column] = $r[0];

$column = $column + 1;

}

mysql_free_result($result);

}

$temp = $_GET[$colname[0]];

$query = "select * from $tablename where $colname[0]=$temp";

$result = mysql_db_query($database,$query);

$r = mysql_fetch_array($result);

?>

<form method="post" action="editdb.php">

<table width=90% align=center>

<tr><td><?php echo "$colname[0]";?>:</td><td><?php echo "$r[0]"; ?></td></tr>

<?

for ($col=1;$col<$column;$col++)

echo "<tr><td>$colname[$col]:</td><td><input type=text name=$colname[$col] size="100%" value="$r[$col]"></td></tr>";

?>

<input type=hidden name=id value="<?php echo "$r[0]"; ?>">

<input type=hidden name=tablename value="<?php echo"$tablename";?>">

<tr><td></td><td><input type=submit value="Confirm!"></td></tr>

</table>

</form>

</body>

</html>

最后是写入数据库

//editdb.php

<?

$database = "sunsite";

$tablename = $_POST['tablename'];

mysql_connect("localhost","root","") or die ("Problem connecting to DataBase");

$query = "show columns from $tablename";

$result = mysql_db_query($database,$query);

$column = 0;

if ($result)

{

while ($r = mysql_fetch_array($result))

{

$colname[$column] = $r[0];

$column = $column + 1;

}

mysql_free_result($result);

}

for($col=0;$col<$column;$col++)

$para[$col] = $_POST[$colname[$col]];

if ($_POST['name'])

{

mysql_connect("localhost","root","") or die ("Problem connecting to DataBase");

$query = "update $tablename set $colname[1]='$para[1]'";

for($col=2;$col<$column;$col++)

$query = $query . ",$colname[$col]='$para[$col]'";

$query = $query . " where $colname[0]='$para[0]';";

$result = mysql_db_query($database, $query);

Header("Location: edit.php?tablename=$tablename");

}

else

{

echo "No name Entered. Please go back and reenter name";

}

?>

<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />

待续。

 
 
 
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