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最近比较空闲，研究了一下手机游戏中的寻路算法
小地图中，解决的方式就不说了，怎么解决都差不多，假如地图比较大，就要好好考虑了
gameloft的彩虹六号里面的寻路算法就很经典，但据说他们是发明了一种专利算法，具体的我就不知道了~但我估计应该是在地图里面设置了一些路点之类的标志。。。。。
我今天贴的代码完全是别人的代码，我也没改动，也没有测试过内存占用，紧紧提供给大家一个大体思路，各位兄弟具体使用时肯定还需要修改的。尤其对于内存资源比较紧张的手机来说，A*算法的改进绝对值得各位好好研究
相关资料：
A*寻路算法(For 初学者)
在A*寻路中使用二*堆
Enjoy:)
--------------------------source code----------------------------------------------
/**
* AStar pathfinding algorithm
*/
public class AStar {
private Square[][] squares;
public static final byte WALL = 0x1, BLANK = 0x0;
public static final byte WALL_MASK = (byte) 0xf;
public static final byte OPEN_MASK = (byte) 0x80;
public static final byte CLOSED_MASK = (byte) 0x40;
private byte[][] map;
private Square lStart;
private Square lEnd;
private static final byte ORTHOGONAL_COST = 1;
byte height;
byte width;
// Binary Heap
public Square[] heapTree;
public int heapSize;
boolean first = true;
void updateMap(byte[][] mapMatrix) {
if (map != null) {
map = null;
releaseFind();
} else {
lStart = new Square((byte) 0, (byte) 0, (byte) 0, (byte) 0);
lEnd = new Square((byte) 0, (byte) 0, (byte) 0, (byte) 0);
heapTree = new Square[height * width + 1];
squares = new Square[height][width];
}
map = mapMatrix;
}
public void releaseFind() {
int i, j;
for (i = 0; i < height; i++) {
for (j = 0; j < width; j++) {
squares[i][j] = null;
}
}
for (i = 0; i < heapTree.length; i++) {
heapTree[i] = null;
}
}
public Square findPath(byte sy, byte sx, byte ey, byte ex, boolean canfly) {
lStart.X = sx;
lStart.Y = sy;
lEnd.X = ex;
lEnd.Y = ey;
if (canfly) {
Square sqr, last;
last = lStart;
int sign;
if (ex != sx) {
sign = (ex - sx) / Math.abs(ex - sx);
for (byte i = (byte) (sx + sign); i != ex; i += sign) {
sqr = new Square(sy, i, (byte) 0, (byte) 0);
sqr.parent = last;
last = sqr;
}
}
if (ey != sy) {
sign = (ey - sy) / Math.abs(ey - sy);
for (byte i = (byte) (sy); i != ey; i += sign) {
sqr = new Square(i, ex, (byte) 0, (byte) 0);
sqr.parent = last;
last = sqr;
}
}
lEnd.parent = last;
return lEnd;
}