integer to String : int i = 42; String str = Integer.toString(i);
or
String str = "" + i
double to String : String str = Double.toString(i);
long to String : String str = Long.toString(l);
float to String : String str = Float.toString(f);
String to integer : str = "25"; int i = Integer.valueOf(str).intValue();
or
int i = Integer.parseInt(str);
String to double : double d = Double.valueOf(str).doubleValue();
String to long : long l = Long.valueOf(str).longValue();
or
long l = Long.parseLong(str);
String to float : float f = Float.valueOf(str).floatValue();
decimal to binary : int i = 42; String binstr = Integer.toBinaryString(i);
decimal to hexadecimal : int i = 42; String hexstr = Integer.toString(i, 16);
or
String hexstr = Integer.toHexString(i);
hexadecimal (String) to integer : int i = Integer.valueOf("B8DA3", 16).intValue();
or
int i = Integer.parseInt("B8DA3", 16);
ASCII code to String : int i = 64; String aChar = new Character((char)i).toString();
integer to ASCII code (byte) : char c = 'A'; int i = (int) c; // i will have the value 65 decimal
To extract Ascii codes from a String : String test = "ABCD";
for ( int i = 0; i < test.length(); ++i ) {
char c = test.charAt( i );
int i = (int) c;
System.out.println(i);
}
integer to boolean : b = (i != 0);
boolean to integer : i = (b)?1:0;
note :To catch illegal number conversion, try using the try/catch mechanism.
try{
i = Integer.parseInt(aString);
} catch(NumberFormatException e) { }
