Oracle SQL中的RANK

王朝oracle·作者佚名  2008-05-31
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RANK is an Analytical Function that can be used to get the rank of a row in respect to a group of rows. This little example will demonstrate this. First you have to create and load a table that contains each month's average temprature in Edinburgh in the years 1764-1820. The script to do that can be found here.

After filling this table, RANK can be used to query the hottest month in each year:

set feedback off

set pages 50000

select month,year,avg_temp from

(select rank() over (partition by year order by avg_temp desc) r, avg_temp, month, year from scottish_weather)

where r=1;

This returns:

MONTH YEAR AVG_TEMP

---------- ---------- ----------

7 1764 59,9

7 1765 58,5

8 1766 59,5

8 1767 59,8

8 1768 58,7

7 1769 60,1

8 1770 58,2

7 1771 57,4

7 1772 58

8 1773 58,3

7 1774 56,8

7 1775 59,7

7 1776 59,6

8 1777 59,2

7 1778 61,2

7 1779 65,2

8 1780 63,2

7 1781 60,4

7 1782 60,1

7 1783 63,2

7 1784 58,5

6 1785 60,7

8 1786 58,7

7 1787 60

8 1787 60

7 1788 60,3

8 1789 61,6

7 1790 59

7 1791 58,6

8 1792 60,3

7 1793 60

7 1794 60,7

8 1795 59,3

8 1796 59,5

7 1797 60,9

6 1798 60,8

7 1799 58

7 1800 61,6

8 1801 60,4

8 1802 60,1

7 1803 62,8

6 1804 59,6

8 1805 59,4

8 1806 58,8

7 1807 61

7 1808 62,5

8 1809 57,4

8 1810 58

7 1811 59,3

8 1812 57,2

7 1813 59,3

7 1814 59,4

7 1815 58,2

7 1816 55,7

7 1817 57,2

7 1818 60

8 1819 62,7

7 1820 59

Note: two rows are returned for the year 1787 because the hottest average temperature are the same for July and August.

Using Rank to select a month's last record

create table test_month (

val number,

dtdate

);

alter session set nls_date_format = 'DD.MM.YYYY';

insert into test_month (val,dt) values (18,'28.08.2000');

insert into test_month (val,dt) values (19,'02.08.2000');

insert into test_month (val,dt) values (22,'27.09.2000');

insert into test_month (val,dt) values (23,'04.09.2000');

insert into test_month (val,dt) values (20,'12.08.2000');

insert into test_month (val,dt) values (24,'15.09.2000');

insert into test_month (val,dt) values (19,'27.07.2000');

insert into test_month (val,dt) values (18,'01.07.2000');

insert into test_month (val,dt) values (21,'26.07.2000');

insert into test_month (val,dt) values (24,'03.06.2000');

insert into test_month (val,dt) values (22,'11.07.2000');

insert into test_month (val,dt) values (21,'14.06.2000');

select val,dt from (select

val,dt,rank() over(partition by to_char(dt,'YYYY.MM') order by dt desc) rn

from test_month

)

where rn = 1;

VAL DT

---------- ----------

21 14.06.2000

19 27.07.2000

18 28.08.2000

22 27.09.2000

Links

See also Top N Query that shows how to perform a top n query with rank.

 
 
 
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