前一阵在导出数据时遇见的问题,后来在网上找到这篇文章,写的不错,大家分享一下.ORA-01555 "Snapshot too old" - Detailed EXPlanation
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ORA-01555 快照过旧--具体解释
Overview
~~~~~~~~
概述
This article will discuss the circumstances under which a query can return the
Oracle error ORA-01555 "snapshot too old (rollback segment too small)". The
article will then proceed to discuss actions that can be taken to avoid the
error and finally will provide some simple PL/SQL scripts that illustrate the
issues discussed.
本文将讨论查询返回 ORA-01555”快照过旧”(回滚段太小).本文将进一步探讨防止此错误的措施,并最终提供一些简单的用于演示的PL/SQL脚本.
Terminology
~~~~~~~~~~~
术语
It is assumed that the reader is familiar with standard Oracle terminology sUCh
as 'rollback segment' and 'SCN'. If not, the reader should first read the Oracle
Server Concepts manual and related Oracle documentation.
读者需要熟悉标准Oracle术语,如”回滚段”与”SCN”.否则,应当首先阅读Oracle Server Concepts手册与相关文档.
In addition to this, two key concepts are briefly covered below which help in
the understanding of ORA-01555:
进一步的,有助于理解ORA-01555的两个要害概念概述如下 :
1. READ CONSISTENCY:
====================
1. 读一致性
This is documented in the Oracle Server Concepts manual and so will not be
discussed further. However, for the purposes of this article this should be read
and understood if not understood already.
文档可见Oracle Server Concepts,此处不深入讨论.但,为理解本文,如尚未理解,请阅读并理解.Oracle Server has the ability to have multi-version read consistency which is
invaluable to you because it guarantees that you are seeing a consistent view of
the data (no 'dirty reads').
Oracle Server支持多版本读一致性,它保证你看到一致的数据(无"脏"数据),这时不可估量的.2. DELAYED BLOCK CLEANOUT:
==========================
2. 延迟的块清出This is best illustrated with an example: Consider a transaction that updates a
million row table. This obviously visits a large number of database blocks to
make the change to the data. When the user commits the transaction Oracle does
NOT go back and revisit these blocks to make the change permanent. It is left
for the next transaction that visits any block affected by the update to 'tidy
up' the block (hence the term 'delayed block cleanout').
用一个例子可以很好的说明:考虑一个更新100万行的表的事务.这显然需要访问大量的数据库块以修改数据.当用户提交事务时,Oracle并不重新访问这些块并进行永久性修改.这将留给下一个需要访问此更新涉及块的事务来"清洁"这些块(即,延迟的块清出).Whenever Oracle changes a database block (index, table, cluster) it stores a
pointer in the header of the data block which identifies the rollback segment
used to hold the rollback information for the changes made by the transaction.
(This is required if the user later elects to not commit the changes and wishes
to 'undo' the changes made.)
Oracle修改任一数据库块(索引,表,簇)时,均在数据块头存放一个指针,指向保存有事务修改的回滚信息的回滚段.(这用于防止用户决定不提交更改,并希望"重做"已做的修改).
Upon commit, the database simply marks the relevant rollback segment header
entry as committed. Now, when one of the changed blocks is revisited Oracle
examines the header of the data block which indicates that it has been changed
at some point. The database needs to confirm whether the change has been
committed or whether it is currently uncommitted. To do this, Oracle determines
the rollback segment used for the previous transaction (from the block's header)
and then determines whether the rollback header indicates whether it has been
committed or not.If it is found that the block is committed then the header of the data block is
updated so that subsequent Accesses to the block do not incur this processing.This behaviour is illustrated in a very simplified way below. Here we walk
through the stages involved in updating a data block.STAGE 1 - No changes madeDescription: This is the starting point. At the top of the
data block we have an area used to link active
transactions to a rollback
segment (the 'tx' part), and the rollback segment
header has a table that stores information upon
all the latest transactions
that have used that rollback segment. In our example, we have two active transaction
slots (01 and 02)
and the next free slot is slot 03. (Since we are
free to overwrite committed transactions.)Data Block 500 Rollback Segment Header 5
+----+--------------+ +----------------------+---------+
tx None transaction entry 01 ACTIVE
+----+--------------+ transaction entry 02 ACTIVE
row 1 transaction entry 03 COMMITTED
row 2 transaction entry 04 COMMITTED
... .. ... ... .. ...
row n transaction entry nn COMMITTED
+-------------------+ +--------------------------------+
STAGE 2 - Row 2 is updatedDescription: We have now updated row 2 of block 500. Note that
the data block header is updated to point to the
rollback segment 5, transaction
slot 3 (5.3) and that it is marked uncommitted
(Active). Data Block 500 Rollback Segment Header 5
+----+--------------+ +----------------------+---------+
tx 5.3uncommitted-+ transaction entry 01 ACTIVE
+----+--------------+ transaction entry 02 ACTIVE
row 1 +--> transaction entry 03 ACTIVE
row 2 *changed* transaction entry 04 COMMITTED
... .. ... ... .. ...
row n transaction entry nn COMMITTED
+------------------+ +--------------------------------+STAGE 3 - The user issues a commitDescription: Next the user hits commit. Note that all that
this does is it
updates the rollback segment header's
corresponding transaction
slot as committed. It does *nothing* to the data
block.Data Block 500 Rollback Segment Header 5
+----+--------------+ +----------------------+---------+
tx 5.3uncommitted--+ transaction entry 01 ACTIVE
+----+--------------+ transaction entry 02 ACTIVE
row 1 +---> transaction entry 03 COMMITTED
row 2 *changed* transaction entry 04 COMMITTED
... .. ... ... .. ...
row n transaction entry nn COMMITTED
+------------------+ +--------------------------------+
STAGE 4 - Another user selects data block 500Description: Some time later another user (or the same user)
revisits data block 500. We can see that there
is an uncommitted change in the
data block according to the data block's header. Oracle then uses the data block header to look up
the corresponding rollback segment transaction
table slot, sees that it has been committed, and
changes data block 500 to reflect the
true state of the datablock. (i.e. it performs
delayed cleanout).Data Block 500 Rollback Segment Header 5
+----+--------------+ +----------------------+---------+
tx None transaction entry 01 ACTIVE
+----+--------------+ transaction entry 02 ACTIVE
row 1 transaction entry 03 COMMITTED
row 2 transaction entry 04 COMMITTED
... .. ... ... .. ...
row n transaction entry nn COMMITTED
+------------------+ +--------------------------------+
ORA-01555 Explanation
~~~~~~~~~~~~~~~~~~~~~There are two fundamental causes of the error ORA-01555 that are a result of
Oracle trying to attain a 'read consistent' image. These are : o The rollback information itself is overwritten so that Oracle is unable to
rollback the (committed) transaction entries to attain a sufficiently old enough
version of the block. o The transaction slot in the rollback segment's transaction table (stored in
the rollback segment's header) is overwritten, and Oracle cannot rollback the
transaction header sufficiently to derive the original rollback segment
transaction slot.
Both of these situations are discussed below with the series of steps that cause
the ORA-01555. In the steps, reference is made to 'QENV'. 'QENV' is short for
'Query Environment', which can be thought of as the environment that existed
when a query is first started and to which Oracle is trying to attain a read
consistent image. Associated with this environment is the SCN
(System Change Number) at that time and hence, QENV 50 is the query environment
with SCN 50. CASE 1 - ROLLBACK OVERWRITTENThis breaks down into two cases: another session overwriting the rollback that
the current session requires or the case where the current session overwrites
the rollback information that it requires. The latter is discussed in this
article because this is usually the harder one to understand. Steps: 1. Session 1 starts query at time T1 and QENV 50 2. Session 1 selects block B1 during this query 3. Session 1 updates the block at SCN 51 4. Session 1 does some other work that generates rollback information. 5. Session 1 commits the changes made in steps '3' and '4'.
(Now other transactions are free to overwrite this rollback information) 6. Session 1 revisits the same block B1 (perhaps for a different row). Now, Oracle can see from the block's header that it has been changed and
it is later than the required QENV (which was 50). Therefore we need to get an
image of the block as of this QENV. If an old enough version of the block can be found in the buffer cache
then we will use this, otherwise we need to rollback the current block to
generate another version of the block as at the required QENV. It is under this condition that Oracle may not be able to get the
required rollback information because Session 1's changes have generated
rollback information that has overwritten it and returns the ORA-1555 error.CASE 2 - ROLLBACK TRANSACTION SLOT OVERWRITTEN 1. Session 1 starts query at time T1 and QENV 50 2. Session 1 selects block B1 during this query 3. Session 1 updates the block at SCN 51 4. Session 1 commits the changes
(Now other transactions are free to overwrite this rollback information) 5. A session (Session 1, another session or a number of other sessions) then
use the same rollback segment for a series of committed transactions. These transactions each consume a slot in the rollback segment
transaction table such that it eventually wraps around (the slots are written to
in a circular fashion) and overwrites all the slots. Note that Oracle is free to
reuse these slots since all transactions are committed.
6. Session 1's query then visits a block that has been changed since the
initial QENV was established. Oracle therefore needs to derive(获得) an image of the
block as at that point in time. Next Oracle attempts to lookup the rollback segment header's transaction
slot pointed to by the top of the data block. It then realises that this has
been overwritten and attempts to rollback the changes made to the rollback
segment header to get the original transaction slot entry. If it cannot rollback the rollback segment transaction table sufficiently
it will return ORA-1555 since Oracle can no longer derive the required version
of the data block.
It is also possible to encounter a variant of the transaction slot being
overwritten when using block cleanout. This is briefly described below :Session 1 starts a query at QENV 50. After this another process updates the
blocks that Session 1 will require. When Session 1 encounters these blocks it
determines that the blocks have changed and have not yet been cleaned out (via
delayed block cleanout). Session 1 must determine whether the rows in the block
existed at QENV 50, were subsequently changed,In order to do this, Oracle must look at the relevant rollback segment
transaction table slot to determine the committed SCN. If this SCN is after the
QENV then Oracle must try to construct an older version of the block and if it
is before then the block just needs clean out to be good enough for the QENV.If the transaction（处理） slot has been overwritten and the transaction table cannot
be rolled back to a sufficiently old enough version then Oracle cannot derive
the block image and will return ORA-1555.(Note: Normally Oracle can use an algorithm for determining a block's SCN
during block cleanout even when the rollback segment slot has been overwritten.
But in this case Oracle cannot guarantee that the version of the block has not
changed since the start of the query).Solutions解决问题的办法
~~~~~~~~~This section lists some of the solutions that can be used to avoid（避免）the ORA-01555
problems discussed in this article. It addresses the cases where rollback
segment information is overwritten by the same session and when the rollback
segment transaction table entry is overwritten. It is worth highlighting（最重要的） that if a single session experiences the ORA-01555 and
it is not one of the special cases listed at the end of this article, then the
session must be using an Oracle extension延伸 whereby由此 fetches across commits are
tolerated. This does not follow the ANSI model and in the rare cases where
ORA-01555 is returned one of the solutions below must be used.CASE 1 - ROLLBACK OVERWRITTEN
1. Increase size of rollback segment which will reduce the likelihood of
overwriting rollback information that is needed. 2. Reduce the number of commits (same reason as 1). 3. Run the processing against a range of data rather than the whole table.
(Same reason as 1). 4. Add additional（附加） rollback segments. This will allow the updates etc. to be
spread across more rollback segments thereby reducing the chances of overwriting
required rollback information. 5. If fetching across commits, the code can be changed so that this is not
done. 6. Ensure that the outer select does not revisit the same block at different
times during the processing. This can be achieved by : - Using a full table scan rather than an index lookup
- Introducing a dummy sort so that we retrieve all the data, sort it and
then sequentially visit these data blocks.CASE 2 - ROLLBACK TRANSACTION SLOT OVERWRITTEN 1. Use any of the methods outlined above except for '6'. This will allow
transactions to spread their work across multiple rollback segments therefore
reducing the likelihood or rollback segment transaction table slots being
consumed. 2. If it is suspected that the block cleanout variant is the cause, then force
block cleanout to occur prior to the transaction that returns the ORA-1555. This
can be achieved by issuing the following in SQL*Plus, SQL*DBA or Server Manager
: alter session set optimizer_goal = rule;
select count(*) from table_name; If indexes are being accessed then the problem may be an index block and
clean out can be forced by ensuring that all the index is traversed. Eg, if the
index is on a numeric column with a minimum value of 25 then the following query
will force cleanout of the index : select index_column from table_name where index_column > 24;Examples
~~~~~~~~Listed below are some PL/SQL examples that can be used to illustrate the
ORA-1555 cases given above. Before these PL/SQL examples will return this error
the database must be configured as follows : o Use a small buffer cache (db_block_buffers).
REASON: You do not want the session executing the script to be able to find
old versions of the block in the buffer cache which can be used to satisfy a
block visit without requiring the rollback information. o Use one rollback segment other than SYSTEM. REASON: You need to ensure that the work being done is generating rollback
information that will overwrite the rollback information required.
o Ensure that the rollback segment is small. REASON: See the reason for using one rollback segment.ROLLBACK OVERWRITTENrem * 1555_a.sql -
rem * Example of getting ora-1555 "Snapshot too old" by
rem * session overwriting the rollback information required
rem * by the same session. drop table bigemp;
create table bigemp (a number, b varchar2(30), done char(1)); drop table dummy1;
create table dummy1 (a varchar2(200)); rem * Populate the example tables.
begin
for i in 1..4000 loop
insert into bigemp values (mod(i,20), to_char(i), 'N');
if mod(i,100) = 0 then
insert into dummy1 values ('ssssssssssss');
commit;
end if;
end loop;
commit;
end;
/ rem * Ensure that table is 'cleaned out'.
select count(*) from bigemp; declare
-- Must use a predicate so that we revisit a changed block at a different
-- time. -- If another tx is updating the table then we may not need the predicate
cursor c1 is select rowid, bigemp.* from bigemp where a < 20; begin
for c1rec in c1 loop update dummy1 set a = 'aaaaaaaa';
update dummy1 set a = 'bbbbbbbb';
update dummy1 set a = 'cccccccc';
update bigemp set done='Y' where c1rec.rowid = rowid;
commit;
end loop;
end;
/ROLLBACK TRANSACTION SLOT OVERWRITTEN rem * 1555_b.sql - Example of getting ora-1555 "Snapshot too old" by
rem * overwriting the transaction slot in the rollback
rem * segment header. This just uses one session. drop table bigemp;
create table bigemp (a number, b varchar2(30), done char(1)); rem * Populate demo table.
begin
for i in 1..200 loop
insert into bigemp values (mod(i,20), to_char(i), 'N');
if mod(i,100) = 0 then
commit;
end if;
end loop;
commit;
end;
/ drop table mydual;
create table mydual (a number);
insert into mydual values (1);
commit; rem * Cleanout demo table.
select count(*) from bigemp;
declare cursor c1 is select * from bigemp; begin -- The following update is required to illustrate the problem if block
-- cleanout has been done on 'bigemp'. If the cleanout (above) is commented
-- out then the update and commit statements can be commented and the
-- script will fail with ORA-1555 for the block cleanout variant.
update bigemp set b = 'aaaaa';
commit; for c1rec in c1 loop
for i in 1..20 loop
update mydual set a=a;
commit;
end loop;
end loop;
end;
/Special Cases
~~~~~~~~~~~~~There are other special cases that may result in an ORA-01555. These are given
below but are rare and so not discussed in this article :o Trusted Oracle can return this if configured in OS MAC mode. Decreasing
LOG_CHECKPOINT_INTERVAL on the secondary database may overcome the problem.o If a query visits a data block that has been changed by using the Oracle
discrete transaction facility then it will return ORA-01555.o It is feasible that a rollback segment created with the OPTIMAL clause
maycause a query to return ORA-01555 if it has shrunk during the life of the
query causing rollback segment information required to generate consistent read
versions of blocks to be lost.Summary
~~~~~~~This article has discussed the reasons behind the error ORA-01555 "Snapshot too
old", has provided a list of possible methods to avoid the error when it is
encountered, and has provided simple PL/SQL scripts that illustrate the cases
discussed.
