开发技巧:JAVA编程中字符串分割的两种方法

王朝java/jsp·作者佚名  2008-06-01
窄屏简体版  字體: |||超大  

方法1:采用String的split,验证代码如下:

import Java.util.Arrays;

public class TestSplit {

public static void main(String[] args) {

String orignString = new String("5,8,7,4,3,9,1");

String[] testString = orignString.split(",");

int[] test = { 0, 0, 0, 0, 0, 0, 0 };

//String to int

for (int i = 0; i < testString.length; i++) {

test[i] = Integer.parseInt(testString[i]);

}

//sort

Arrays.sort(test);

//asc sort

for (int j = 0; j < test.length; j++) {

System.out.println(test[j]);

}

System.out.println("next ");

// desc

for (int i = (test.length - 1); i >= 0; i--) {

System.out.println(test[i]);

}

}

}

方法2:采用StringTokenizer

import java.util.Arrays;

import java.util.StringTokenizer;

public class SplitStringTest {

public static void main(String[] args) {

String s = new String("5,8,7,4,3,9,1");

int length = s.length();

//split s with ","

StringTokenizer commaToker = new StringTokenizer(s, ",");

String[] result = new String[commaToker.countTokens()];

int k = 0;

while (commaToker.hasMoreTokens()) {

result[k] = commaToker.nextToken();

k++;

}

int[] a = new int[result.length];

for (int i = 0; i < result.length; i++) {

a[i] = Integer.parseInt(result[i]);

}

//sort

Arrays.sort(a);

//asc sort

for (int j = 0; j < result.length; j++) {

System.out.println(a[j]);

}

}

}

 
 
 
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