查找日期为某一天的文件
技巧管理员(2000-12-22 23:24)
〖返回〗〖转发〗
A=`find ~ -print` | ls -l --full-time $A 2>/dev/null | grep "Jun 27" | grep 1998
Linux的命令很厉害的呀！
给你写了下面这个script，用着方便点儿。你把它存成一个随便什么名字的文件,置上x属性就行了。
#!/bin/sh
# The right of usage, distribution and modification is here by granted by the author.
# The author deny any responsibilities and liabilities related to the code.
#
OK=0
A=`find $1 -print`
if expr $3 == 1 >/dev/null ; then M=Jan ; OK=1 ; fi
if expr $3 == 2 >/dev/null ; then M=Feb ; OK=1 ; fi
if expr $3 == 3 >/dev/null ; then M=Mar ; OK=1 ; fi
if expr $3 == 4 >/dev/null ; then M=Apr ; OK=1 ; fi
if expr $3 == 5 >/dev/null ; then M=May ; OK=1 ; fi
if expr $3 == 6 >/dev/null ; then M=Jun ; OK=1 ; fi
if expr $3 == 7 >/dev/null ; then M=Jul ; OK=1 ; fi
if expr $3 == 8 >/dev/null ; then M=Aug ; OK=1 ; fi
if expr $3 == 9 >/dev/null ; then M=Sep ; OK=1 ; fi
if expr $3 == 10 >/dev/null ; then M=Oct ; OK=1 ; fi
if expr $3 == 11 >/dev/null ; then M=Nov ; OK=1 ; fi
if expr $3 == 12 >/dev/null ; then M=Dec ; OK=1 ; fi
if expr $3 == 1 >/dev/null ; then M=Jan ; OK=1 ; fi
if expr $OK == 1 > /dev/null ; then
ls -l --full-time $A 2>/dev/null | grep "$M $4" | grep $2 ;
else
echo Usage: $0 path Year Month Day;
echo Example: $0 ~ 1998 6 30;
fi
