最近做一个数据库，要用到大写的金额格式显示，于是自己写了一个，希望大家多提宝贵意见！（真是感到了C++ Builder的资料短缺了，连现成的这个函数都找不到！）
AnsiString CurrToChnNum(float CurrNum, bool DisplayZero = true, int SpaceNum = 2);
AnsiString CurrToChnNum(float CurrNum, bool DisplayZero, int SpaceNum)
//参数说明：CurrNum 这个是要转化的数值
DisplayZero 是否要显示零如：(显示零)壹佰 零拾 叁元 伍角 伍分
SpaceNum 字符间的空格数，默认值为2
{
//数值转换为大写金额
//18个数字单位
const String Dw[18] = {"分","角","元","拾","佰","仟","万","拾","佰","仟","亿","拾","佰","仟","兆","拾","佰","仟"};
//10个数码
const String Num[10] = {"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"};
AnsiString sTemp;
sTemp = FormatFloat("0.00", CurrNum); //格式化数值
sTemp.Delete(sTemp.Pos("."), 1); //去掉小数点
if ( sTemp.Length() > 18 ) //是否超长？
{
MessageDlg("数值位数太多，不能处理！",mtError,TMsgDlgButtons() << mbYes,0);
return NULL;
}
AnsiString sRusult = "￥ "; //字串的头部字符，根据喜好
for (int i = sTemp.Length(); i > 0; i--) //开始加工
{
if ( !DisplayZero && i > 2 && sTemp[sTemp.Length() - i + 1] - 48 == 0 )
continue;
sRusult += Num[sTemp[sTemp.Length()-i+1]-48];
sRusult += Dw[i-1];
sRusult += AnsiString::StringOfChar(' ', SpaceNum);
}
return sRusult;
}
//---------------------------------------------------------------------------
