判断字符串是否是合法的EMail

王朝vb·作者佚名  2006-01-08
窄屏简体版  字體: |||超大  

Public Function IsValidEmail(strEmail As String) As Boolean

Dim names, name, i, c

IsValidEmail = True

names = Split(strEmail, "@")

If UBound(names) <> 1 Then

IsValidEmail = False

Exit Function

End If

For Each name In names

If Len(name) <= 0 Then

IsValidEmail = False

Exit Function

End If

For i = 1 To Len(name)

c = LCase(Mid(name, i, 1))

If InStr("abcdefghijklmnopqrstuvwxyz_-.", c) <= 0 And Not IsNumeric(c) Then

IsValidEmail = False

Exit Function

End If

Next

If Left(name, 1) = "." Or Right(name, 1) = "." Then

IsValidEmail = False

Exit Function

End If

Next

If InStr(names(1), ".") <= 0 Then

IsValidEmail = False

Exit Function

End If

i = Len(names(1)) - InStrRev(names(1), ".")

If i <> 2 And i <> 3 Then

IsValidEmail = False

Exit Function

End If

If InStr(strEmail, "..") > 0 Then

IsValidEmail = False

Exit Function

End If

End Function

 
 
 
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