字符串与二进制互相转化(不包含汉字)

王朝vb·作者佚名  2006-01-08
窄屏简体版  字體: |||超大  

对于二进制与字符的互换,是由于我要做DES加密程序的需要才设计的

现在把我的源程序发布:

先建立一个工程

在框架上画

两个textbox,命名为text1,text2

两个commandbutton, 命名为command1,command1

其他定义自己去该吧!

rem 此程序由Qthinker制作,免费发布,可以修改,请保留此信息

Option Base 1

Private Function byte2bit(s As String) As String

Dim i As Integer, j As Integer, k As Integer, ilen As Integer

Dim by() As String

Dim b() As Integer

ilen = Len(s)

ReDim by(ilen)

ReDim b(ilen / 8)

For k = 1 To ilen

by(k) = Mid$(s, k, 1)

Next k

For i = 1 To (ilen / 8)

If by(1 + 8 * (i - 1)) = "1" Then

b(i) = b(i) Or &H80

Else

b(i) = b(i) And &H7F

End If

If by(2 + 8 * (i - 1)) = "1" Then

b(i) = b(i) Or &H40

Else

b(i) = b(i) And &HBF

End If

If by(3 + 8 * (i - 1)) = "1" Then

b(i) = b(i) Or &H20

Else

b(i) = b(i) And &HDF

End If

If by(4 + 8 * (i - 1)) = "1" Then

b(i) = b(i) Or &H10

Else

b(i) = b(i) And &HEF

End If

If by(5 + 8 * (i - 1)) = "1" Then

b(i) = b(i) Or &H8

Else

b(i) = b(i) And &HF7

End If

If by(6 + 8 * (i - 1)) = "1" Then

b(i) = b(i) Or &H4

Else

b(i) = b(i) And &HFB

End If

If by(7 + 8 * (i - 1)) = "1" Then

b(i) = b(i) Or &H2

Else

b(i) = b(i) And &HFD

End If

If by(8 + 8 * (i - 1)) = "1" Then

b(i) = b(i) Or "1"

Else

b(i) = b(i) And &HFE

End If

byte2bit = byte2bit & Chr$(b(i))

Next i

End Function

Private Function bit2byte(s As String) As String

Dim s2 As String

Dim x As String

Dim i As Integer, k As Integer

Dim ilen As Integer

ilen = Len(s)

Dim b()

Dim s1()

ReDim s1(ilen)

ReDim b(ilen * 8)

s2 = ""

For i = 1 To ilen

x = Mid$(s, i, 1)

s1(i) = Asc(x)

If s1(i) And &H80 Then

b(1 + 8 * (i - 1)) = 1

Else

b(1 + 8 * (i - 1)) = 0

End If

If s1(i) And &H40 Then

b(2 + 8 * (i - 1)) = 1

Else

b(2 + 8 * (i - 1)) = 0

End If

If s1(i) And &H20 Then

b(3 + 8 * (i - 1)) = 1

Else

b(3 + 8 * (i - 1)) = 0

End If

If s1(i) And &H10 Then

b(4 + 8 * (i - 1)) = 1

Else

b(4 + 8 * (i - 1)) = 0

End If

If s1(i) And &H8 Then

b(5 + 8 * (i - 1)) = 1

Else

b(5 + 8 * (i - 1)) = 0

End If

If s1(i) And &H4 Then

b(6 + 8 * (i - 1)) = 1

Else

b(6 + 8 * (i - 1)) = 0

End If

If s1(i) And &H2 Then

b(7 + 8 * (i - 1)) = 1

Else

b(7 + 8 * (i - 1)) = 0

End If

If s1(i) And "1" Then

b(8 + 8 * (i - 1)) = 1

Else

b(8 + 8 * (i - 1)) = 0

End If

Next i

For k = 1 To ilen * 8

s2 = s2 & b(k)

If k Mod 8 = 0 Then

s2 = s2

End If

Next k

bit2byte = s2

End Function

Private Sub Command1_Click()

Dim s As String

Dim s2 As String

s = Text1.Text

s2 = bit2byte(s)

Text2.Text = s2

End Sub

Private Sub Command2_Click()

Dim s As String

Dim s1 As String

s = Text2.Text

s1 = byte2bit(s)

Text2.Text = s1

End Sub

 
 
 
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