编一个有十个节点的链表

#include<iostream.h>

class node//

{

public:

node *next;

int data;

node(const int & item ,node *ptrnext=NULL);//构造

void insertafter(node*p);//插入

node *thisnode(void);//返回本节点的指针

};

node::node(const int&item,node *ptrnext)

{

data=item;

next=ptrnext;

}

void node::insertafter(node*lastptr)

{

lastptr->next=this->next;

this->next=lastptr;

}

node *node::thisnode(void)

{return this;}

void main()

{

int a,i;

node *lastptr,*head,*currptr; cout<<"please input a: "<<endl;

cin>>a;

node example1(a);

head=example1.thisnode();

currptr=head;

for(i=0;i<9;i++)

{

lastptr=example1.thisnode();

cin>>a;

node example1(a);

example1.insertafter(lastptr);

}

cout<<endl;

while (currptr!=NULL)

{

cout<<currptr->data;

currptr=currptr->next;

}

}

请问这个程序应怎样修改？谢谢