C++ :学习Proxy Class之笔记2

王朝c/c++·作者佚名  2006-01-09
窄屏简体版  字體: |||超大  

依然是对more effective c++条款30-Proxy Class的学习笔记。

#include

using namespace std;

template

class Array

{

public:

class Proxy

{

public:

Proxy(Array& array, int index)

: theArray(array), itemIndex(index)

{}

Proxy& operator = (const T& rhs)

{

theArray.array[itemIndex] = rhs;

return *this;

}

operator T() const

{

return theArray.array[itemIndex];

}

private:

Array& theArray;

int itemIndex;

};

const Proxy operator[](int index) const;

Proxy operator[](int index);

friend class Proxy;

Array(int dim);

~Array();

private:

T* array;

};

template

Array::Array(int dim)

{

array = new T[dim];

}

template

Array::~Array()

{

delete [] array;

}

template

Array::Proxy Array::operator[](int index)

{

return Proxy(*this, index);

}

template

const Array::Proxy Array::operator [] (int index) const

{

return Proxy(const_cast(*this), index);}class Rational{public: Rational(int numerator = 0, int denominator = 1); int numerator() const; int denominator() const; friend ostream& operator<<(ostream& os, const Rational& rhs);private: int num; int deno;};Rational::Rational(int numerator, int denominator): num(numerator), deno(denominator){ std::cout << "Rational Construct" << std::endl;}int Rational::numerator() const{ std::cout << "numerator" << std::endl; return 0;}int Rational::denominator() const{ std::cout << "denominator" << std::endl; return 0;}ostream& operator<<(ostream& os, const Rational& rhs){ os << rhs.num << " " << rhs.deno; return os;}int main(){ Array a(5); a[1].numerator(); //错误}之所以出现错误的原因是:operator[] 返回一个代理对象而不是实际的Rational对象。但成员函数numerator()和denominator()只存在于Rational对象上,而不是其代理对象。但是我想,为什么编译器在这里不调用隐式转换函数 operator T() const { return theArray.array[itemIndex]; }呢?如果调用了,那么错误也就应该不会出现了一个简单的解决办法是int main(){ Array a(5); (( Rational ) a[1] ).numerator(); }

 
 
 
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