浙大在线评测 1045 hangover

王朝other·作者佚名  2006-01-09
窄屏简体版  字體: |||超大  

Question:

How far can you make a stack of cards overhang a table? If you have one card, you can create a maximum overhang of half a card length. (We're assuming that the cards must be perpendicular to the table.) With two cards you can make the top card overhang the bottom one by half a card length, and the bottom one overhang the table by a third of a card length, for a total maximum overhang of 1/2 + 1/3 = 5/6 card lengths. In general you can make n cards overhang by 1/2 + 1/3 + 1/4 + ... + 1/(n + 1) card lengths, where the top card overhangs the second by 1/2, the second overhangs tha third by 1/3, the third overhangs the fourth by 1/4, etc., and the bottom card overhangs the table by 1/(n + 1). This is illustrated in the figure below.

The input consists of one or more test cases, followed by a line containing the number 0.00 that signals the end of the input. Each test case is a single line containing a positive floating-point number c whose value is at least 0.01 and at most 5.20; c will contain exactly three digits.

For each test case, output the minimum number of cards necessary to achieve an overhang of at least c card lengths. Use the exact output format shown in the examples.

Example input:

1.00

3.71

0.04

5.19

0.00

Example output:

3 card(s)

61 card(s)

1 card(s)

273 card(s)

Solution:

// 声明:本代码仅供学习之用,请不要作为个人的成绩提交。

// http://blog.csdn.net/mskia

// email: skianet@yahoo.com.cn

#include <iostream.h>

#include <stdlib.h>

int main( void ) {

float fz = 2.0;

short int i;

float temp , n ;

while( cin >> n && n != 0 ) {

fz = 2.0;

temp = 0;

i = 0;

while ( temp <= n ) {

++i ;

temp += 1 / fz ;

++fz;

}

cout << i << " card(s)" << endl;

}

return 0;

}

 
 
 
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