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将IP地址转换为长整型、将长整型转换为IP地址

王朝other·作者佚名  2006-11-24
窄屏简体版  字體: |||超大  

将IP地址转换为长整型

Converts a string ip address ("192.168.0.1") to a Long number (3232235521). One of the reasons to do this would be to store IP addresses in databases. Numbers greatly reduce the size required to store this information.

Inputs: asNewIP - String IP address ("192.168.0.1") to convert to a number.

Returns: Returns a Long Integer representing the IP address (3232235521)

Assumes: This function assumes that your IP address has 4 integers delimited by decimals and that the numbers range from 0 to 255.

Function CLngIP(ByVal asNewIP)

Dim lnResults

Dim lnIndex

Dim lnIpAry

' Split the IP address using the dot as a delimiter

lnIpAry = Split(asNewIP, ".", 4)

' Loop through Each number In the IP address

For lnIndex = 0 To 3

' If we are Not working With the last number...

If Not lnIndex = 3 Then

' Convert the number To a value range that can be parsed from the others

lnIpAry(lnIndex) = lnIpAry(lnIndex) * (256 ^ (3 - lnIndex))

End If

' Add the number To the results

lnResults = lnResults + lnIpAry(lnIndex)

Next

' If storing number within an Access Database,

' The variable Type "Long" ranges from -2147483648 To 2147483647

' You will need To subtract 2147483648 from the number

' before querying the database.

' lnResults = lnResults - 2147483648

' Return the results

CLngIP = lnResults

End Function

将长整型转换为IP地址

Name: Convert LongIP to StringIP

Description: This function converts a Long Number (3232235521) into an IP Address ("192.168.0.1"). Why would you want to do this? Click here.

Inputs: anNewIP - IP Address as a Long Number (no dots)

Returns: Returns the string representation of an IP Address ("192.168.0.1")

Function CStrIP(ByVal anNewIP)

Dim lsResults ' Results To be returned

Dim lnTemp ' Temporary value being parsed

Dim lnIndex ' Position of number being parsed

' If pulling number from an Access Database,

' The variable Type "Long" ranges from -2147483648 To 2147483647

' You will first need To add 2147483648 to the number to parse correctly.

' anNewIP = anNewIP + 2147483648

' Parse highest numbers first

For lnIndex = 3 To 0 Step -1

' Parse the current value For this position

lnTemp = Int(anNewIP / (256 ^ lnIndex))

' Append the number To the final results delimited by a dot

lsResults = lsResults & lnTemp & "."

' Remove the number that we just parsed

anNewIP = anNewIP - (lnTemp * (256 ^ lnIndex))

Next

' Cut off last dot

lsResults = Left(lsResults, Len(lsResults) - 1)

' Return the results

CStrIP = lsResults

End Function

 
 
 
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