VB 二进制,八进制,十进制,十六进制转换

王朝c#·作者佚名  2006-12-17
窄屏简体版  字體: |||超大  

Public Function D_To_B(ByVal Dec As Long) As String

Do

D_To_B = Dec Mod 2 & D_To_B

Dec = Dec \ 2

Loop While Dec

End Function

Public Function B_To_D(ByVal Bin As String) As Integer

Dim i As Long

For i = 1 To Len(Bin)

B_To_D = B_To_D * 2 + Val(Mid(Bin, i, 1))

Next i

End Function

Public Function H_To_B(ByVal Hex As String) As String

Dim i As Long

Dim B As String

Hex = UCase(Hex)

For i = 1 To Len(Hex)

Select Case Mid(Hex, i, 1)

Case "0": B = B & "0000"

Case "1": B = B & "0001"

Case "2": B = B & "0010"

Case "3": B = B & "0011"

Case "4": B = B & "0100"

Case "5": B = B & "0101"

Case "6": B = B & "0110"

Case "7": B = B & "0111"

Case "8": B = B & "1000"

Case "9": B = B & "1001"

Case "A": B = B & "1010"

Case "B": B = B & "1011"

Case "C": B = B & "1100"

Case "D": B = B & "1101"

Case "E": B = B & "1110"

Case "F": B = B & "1111"

End Select

Next i

While Left(B, 1) = "0"

B = Right(B, Len(B) - 1)

Wend

H_To_B = B

End Function

Public Function B_To_H(ByVal Bin As String) As String

Dim i As Long

Dim H As String

If Len(Bin) Mod 4 <> 0 Then

Bin = String(4 - Len(Bin) Mod 4, "0") & Bin

End If

For i = 1 To Len(Bin) Step 4

Select Case Mid(Bin, i, 4)

Case "0000": H = H & "0"

Case "0001": H = H & "1"

Case "0010": H = H & "2"

Case "0011": H = H & "3"

Case "0100": H = H & "4"

Case "0101": H = H & "5"

Case "0110": H = H & "6"

Case "0111": H = H & "7"

Case "1000": H = H & "8"

Case "1001": H = H & "9"

Case "1010": H = H & "A"

Case "1011": H = H & "B"

Case "1100": H = H & "C"

Case "1101": H = H & "D"

Case "1110": H = H & "E"

Case "1111": H = H & "F"

End Select

Next i

B_To_H = H

End Function

 
 
 
免责声明:本文为网络用户发布,其观点仅代表作者个人观点,与本站无关,本站仅提供信息存储服务。文中陈述内容未经本站证实,其真实性、完整性、及时性本站不作任何保证或承诺,请读者仅作参考,并请自行核实相关内容。
 
 
© 2005- 王朝網路 版權所有 導航