蛙蛙推荐:asp实现树型结构

王朝asp·作者佚名  2006-01-09
窄屏简体版  字體: |||超大  

<!--

-----------[test]表生成脚本---------------

if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[test]') and OBJECTPROPERTY(id, N'IsUserTable') = 1)

drop table [dbo].[test]

GO

CREATE TABLE [dbo].[test] (

[id] [int] IDENTITY (1, 1) NOT NULL ,

[str_note] [nvarchar] (50) COLLATE Chinese_PRC_CI_AS NULL ,

[father_id] [int] NULL

) ON [PRIMARY]

GO

-->

<!--

***********************测试数据********************

[id][str_note][father_id]

[1][电脑书籍][0]

[2][软件开发][1]

[3][硬件维修][1]

[4][asp][2]

[5][php][2]

[6][jsp][2]

[7][html][2]

[8][显示器维修][3]

[9][主板维修][3]

[10][显卡维修][3]

[11][vbs基础][4]

[12][html基础][4]

[13][ado基础][4]

[14][do语句][11]

[15][for语句][11]

[16][select语句][11]

***************************************************

-->

<%

Dim strconn,conn,rs,sql

strconn="Driver={sql server};server=localhost;database=wawavote;uid=sa;pwd=sa;"

Dim i

i=0

Function ShowTree(parentID)

i=i+1

Dim rs

Set rs = Server.CreateObject("ADODB.RecordSet")

sql="SELECT id, str_note, father_id,(SELECT str_note FROM test t2 WHERE t2.id = t1.father_id) AS ParentName FROM test t1 WHERE t1.father_id="&Cint(parentID)

rs.open sql,strconn,1,1

Do While Not rs.Eof

for j=1 to i

Response.Write("---")

next

Response.Write(rs(1)&"["&rs(3)&"]<br>")

ShowTree rs(0)

i=i-1

rs.Movenext

Loop

rs.Close:Set rs=Nothing

End Function

Sub ShowTable(table)

Dim rs

Set rs = Server.CreateObject("ADODB.RecordSet")

sql="select * from "&trim(table)

rs.open sql,strconn,1,1

For i=0 To rs.Fields.Count-1

Response.Write("["&rs.fields(i).Name&"]")

next

Response.Write("<br>")

Do While Not rs.Eof

For i=0 To rs.Fields.Count-1

Response.Write("["&rs.fields(i).Value&"]")

next

Response.Write("<br>")

rs.MoveNext

Loop

rs.Close:Set rs=Nothing

End sub

ShowTree(0)

ShowTable("test")

%>

 
 
 
免责声明:本文为网络用户发布,其观点仅代表作者个人观点,与本站无关,本站仅提供信息存储服务。文中陈述内容未经本站证实,其真实性、完整性、及时性本站不作任何保证或承诺,请读者仅作参考,并请自行核实相关内容。
 
 
© 2005- 王朝網路 版權所有 導航