sicp习题试解 (1.32)

王朝other·作者佚名  2006-01-09
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; ======================================================================

;

; Structure and Interpretation of Computer Programs

; (trial answer to excercises)

;

; 计算机程序的构造和解释(习题试解)

;

; created: code17 03/05/05

; modified:

; (保持内容完整不变前提下,可以任意转载)

; ======================================================================

;; SICP No.1.32

;; 递归版本

(define (accumulate-r combiner null-value term a next b)

(if (> a b)

null-value

(combiner (term a)

(accumulate-r combiner null-value term (next a) next b))))

;; 迭代版本

(define (accumulate-i combiner null-value term a next b)

(if (> a b)

null-value

(accumulate-i combiner

(combiner null-value (term a))

term (next a) next b)))

;; sum

(define (sum term a next b)

(accumulate-r + 0 term a next b))

;; product

(define (product term a next b)

(accumulate-i * 1 term a next b))

;; Test-it:

;; Welcome to MzScheme version 209, Copyright (c) 2004 PLT Scheme, Inc.

;;

;; ;; 我们已经用基于accumulate-i的product代替的原来的product

;; ;; factorial调用了product, 所得结果与以前一致

;; > (factorial 5)

;; 120

;;

;; ;; 我们已经用基于accumulate-r的sum代替的原来的sum

;; ;; integral调用了sum, 所得结果与以前一致

;; > (integral cube 0 1 0.01)

;; 0.24998750000000042

;; BTW, 我们甚至可以定义更高阶的函数,把比较函数也抽象出来

(define (accumulate-high compare combiner null-value term a next b)

(if (compare a b)

null-value

(accumulate-high compare combiner

(combiner null-value (term a))

term (next a) next b)))

 
 
 
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