在单元测试中使用EasyMock

王朝other·作者佚名  2007-01-01
窄屏简体版  字體: |||超大  

我们每天的开发中都要编写大量的单元测试,很多单元测试的对象是相对独立的,例如一个所得税计算的模块,但是更多的单元测试需要依赖其他的组件或者服务。因此,我们需要EasyMock来无缝的连接这些组件。Mock的意思就是空的,不存在的东西。

EasyMock刚刚发布了2.2版本,它开始使用很多基于jdk 1.5的特性。

下面我们举一个例子:

假设定义一个如下的接口:

public interface ISimpsonService {

IEpisode getEpisode(int number);

}

public interface IEpisode {

int getNumber();

String getTitle();

InputStream getDataAsStream();

}

该接口的实现为

public class ClientSimpsonService implements ISimpsonService {

private ISimpsonService remoteSimpsonService;

public ClientSimpsonService(ISimpsonService remoteSimpsonService) {

this.remoteSimpsonService = remoteSimpsonService;

}

public IEpisode getEpisode(int episodeNumber) {

return null;

}

}

对该服务的单元测试如下

public class ClientSimpsonServiceTest extends TestCase {

public void testClientSimpsonService() {

try {

new ClientSimpsonService(null);

fail("Expected IllegalArgumentException");

} catch (IllegalArgumentException e) {

// expected

}

}

我们可以看到因为没有remoteSimpsonService,所以我们只传一个null给ClientSimpsonService,

这样是无法完成测试的。所以我们把还没有写的remoteSimpsonService用mock替代。

import static org.easymock.EasyMock.createMock;

import junit.framework.TestCase;

public class ClientSimpsonServiceTest extends TestCase {

private ISimpsonService remoteSimpsonServiceMock;

protected void setUp() throws Exception {

super.setUp();

remoteSimpsonServiceMock =

createMock(ISimpsonService.class);

}

public void testClientSimpsonService() {

try {

new ClientSimpsonService(null);

fail("Expected IllegalArgumentException");

} catch (IllegalArgumentException e) {

// expected

}

new ClientSimpsonService(remoteSimpsonServiceMock);

}

}

上面的黑体代码中,我们创建了一个ISimpsonService.class的mock,它拥有和ISimpsonService一样的

接口。

同样的方法,我们可以定义ISimpsonService返回的对象IEpisode

import static org.easymock.EasyMock.createMock;

import static org.easymock.EasyMock.expect;

import static org.easymock.EasyMock.replay;

import static org.easymock.EasyMock.verify;

import junit.framework.TestCase;

public class ClientSimpsonServiceTest extends TestCase {

private IEpisode episode17Mock;

private ISimpsonService remoteSimpsonServiceMock;

protected void setUp() throws Exception {

super.setUp();

episode17Mock = createMock(IEpisode.class);

remoteSimpsonServiceMock =

createMock(ISimpsonService.class);

}

...

public void testGetEpisode() throws Exception {

expect(remoteSimpsonServiceMock.getEpisode(17))

.andReturn(episode17Mock);

replay(remoteSimpsonServiceMock);

ISimpsonService clientSimpsonService =

new ClientSimpsonService(remoteSimpsonServiceMock);

IEpisode result = clientSimpsonService.getEpisode(17);

verify(remoteSimpsonServiceMock);

assertEquals(episode17Mock, result);

}

上文仅仅是抛砖引玉,想了解更多EasyMock,请参看

http://today.java.net/pub/a/today/2006/06/20/getting-started-with-easymock-2.html

 
 
 
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