C#模拟MSN窗体抖动

C#模拟MSN窗体抖动C#模拟MSN窗体抖动

窗体抖动是件很有意思的事情，就让我们看看一起来看看它的原理吧。其实是生成随机数，然后改变Form的左上角的坐标。我用的是循环来弄得，其实可以用timer来控制.

我把抖动分成了两种抖动:1。 生成随机数，改变窗体左上角坐标，然后立即把窗体的坐上角坐标还原，继续循环。2。 生成随机数，改变窗体左上角坐标，循环完毕之后，然后立即把窗体的坐上角坐标还原。

核心代码如下：

//第一种抖动 PRivate void button1_Click(object sender, EventArgs e) { int recordx = this.Left; //保存原来窗体的左上角的x坐标 int recordy = this.Top; //保存原来窗体的左上角的y坐标

Random random = new Random();

for (int i = 0; i < 100; i++) { int x = random.Next(rand); int y = random.Next(rand); if (x % 2 == 0) { this.Left = this.Left + x; } else { this.Left = this.Left - x; } if (y % 2 == 0) { this.Top = this.Top + y; } else { this.Top = this.Top - y; }

this.Left = recordx; //还原原始窗体的左上角的x坐标 this.Top = recordy; //还原原始窗体的左上角的y坐标 } }

//第二种抖动 private void button2_Click(object sender, EventArgs e) { int recordx = this.Left; int recordy = this.Top; Random random = new Random(); for (int i = 0; i < 50; i++) { int x = random.Next(rand); int y = random.Next(rand); if (x % 2 == 0) { this.Left = this.Left + x; } else { this.Left = this.Left - x; } if (y % 2 == 0) { this.Top = this.Top + y; } else { this.Top = this.Top - y; } System.Threading.Thread.Sleep(1); } this.Left = recordx; this.Top = recordy; }