JSP里web.xml实现错误处理页面的制作404,和500

王朝学院·作者佚名  2009-02-12
窄屏简体版  字體: |||超大  

web.xml文件增加如下代码查看复制到剪切板打印

<error-page>

<error-code>404</error-code>

<location>/building.jsp</location>

</error-page>

<error-page>

<error-code>500</error-code>

<location>/error.jsp</location>

</error-page>

<error-page>

<error-code>404</error-code>

<location>/building.jsp</location>

</error-page>

<error-page>

<error-code>500</error-code>

<location>/error.jsp</location>

</error-page>building.jsp查看复制到剪切板打印

<%@ page language="java" contentType="text/html; charset=GBK" isErrorPage="true" pageEncoding="GBK"%>

<%

response.setStatus(HttpServletResponse.SC_OK);

%>

对不起,您请求的页面没有找到!

<%@ page language="java" contentType="text/html; charset=GBK" isErrorPage="true" pageEncoding="GBK"%>

<%

response.setStatus(HttpServletResponse.SC_OK);

%>

对不起,您请求的页面没有找到!error.jsp查看复制到剪切板打印

<%@ page language="java" contentType="text/html; charset=GBK" isErrorPage="true" pageEncoding="GBK"%>

<%@ page import="java.io.*,java.util.*"%>

<%response.setStatus(HttpServletResponse.SC_OK);

%>

<body>

程序发生了错误,有可能该页面正在调试或者是设计上的缺陷.

你可以选择

<a href=<%=request.getContextPath()+"/forum/new.jsp" %>>反馈</a>

提醒我... 或者

<a href="javascript:history.go(-1)">返回上一页</a>

<hr width=80%>

<h2><font color=#DB1260>JSP Error Page</font></h2>

<p>An exception was thrown: <b> <%=exception.getClass()%>:<%=exception.getMessage()%></b></p>

<%

System.out.println("Header....");

Enumeration<String> e = request.getHeaderNames();

String key;

while(e.hasMoreElements()){

key = e.nextElement();

System.out.println(key+"="+request.getHeader(key));

}

System.out.println("Attribute....");

e = request.getAttributeNames();

while(e.hasMoreElements()){

key = e.nextElement();

System.out.println(key+"="+request.getAttribute(key));

}

System.out.println("arameter....");

e = request.getParameterNames();

while(e.hasMoreElements()){

key = e.nextElement();

System.out.println(key+"="+request.getParameter(key));

}

%>

111<%=request.getAttribute("javax.servlet.forward.request_uri") %>

<%=request.getAttribute("javax.servlet.forward.servlet_path") %>

<p>With the following stack trace:</p>

<pre>

<%exception.printStackTrace();

ByteArrayOutputStream ostr = new ByteArrayOutputStream();

exception.printStackTrace(new PrintStream(ostr));

out.print(ostr);

%>

</pre>

<hr width=80%>

</body>

 
 
 
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