分式最小值？

(X^2-x-5)/(x+2)

(x^2-x-5)/(x+2)

=[(x+2)(x-3)+1]/(x+2)

=(x-3)+1/(x+2)

=(x+2)+1/(x+2)-5

≥2-5

=-3

所以最小值是-3

注：题目要限制x>-2