则tanB+tanC=?
參考答案:sinA=sin(B+C)=sinBcosC+cosBsinC
2cosBcosC=sinBcosC+cosBsinC
tanB+tanC=(sinBcosC+cosBsinC)/cosCcosB=2cosBcosC/cosBcosC=2
则tanB+tanC=?
參考答案:sinA=sin(B+C)=sinBcosC+cosBsinC
2cosBcosC=sinBcosC+cosBsinC
tanB+tanC=(sinBcosC+cosBsinC)/cosCcosB=2cosBcosC/cosBcosC=2