先说声谢谢拉!(解题过程)1.求2sin20度+cos10度+tan20度sin10度=2.tanα=1,3sinβ=sin(2α+β),求tan(2α+β)的值
參考答案:2sin20 +cos10 +tan20sin10 =2sin20 +cos10 +sin20 /cos20 *sin10 =(2sin20cos20 +cos10cos20 +sin20sin10 )/cos20 =(sin40 +cos10 )/cos20 =(sin40 +sin80 )/cos20 =(2sin60cos20 )/cos20 =2sin60 =√3
第22题答案