（x+1)(x+2)(x+3)(x+4)-24
參考答案:解：
原式
= [(x+1)(x+4)]*[(x+2)(x+3)] -24
= (x^2+ 5x+ 4)(x^2+ 5x+ 6) -24
= (x^2+ 5x)^2+ 10*(x^2+ 5x) +24 -24
= (x^2+ 5x)*(x^2+ 5x+ 10)
= x(x+5)(x^2+ 5x+ 10)
（x+1)(x+2)(x+3)(x+4)-24
參考答案:解：
原式
= [(x+1)(x+4)]*[(x+2)(x+3)] -24
= (x^2+ 5x+ 4)(x^2+ 5x+ 6) -24
= (x^2+ 5x)^2+ 10*(x^2+ 5x) +24 -24
= (x^2+ 5x)*(x^2+ 5x+ 10)
= x(x+5)(x^2+ 5x+ 10)