设x=√3 -2，则x^6+3x^5+11x^3+2x+1=_____

设x=√3 -2，则x^6+3x^5+11x^3+2x+1=_____同上,需要步骤,谢谢

解：

x^6+3x^5+11x^3+2x+1

=x^3*(x^3+3x^2+11)+2x+1

=x^3*[(x^2*(x+3)+11]+2x+1

=x^3*[(x^2*(√3 -2+3)+11]+2x+1

=x^3*[(x^2*(√3 +1)+11]+2x+1

=x^3*[(√3 -2)*(√3 -2)*(√3 +1)+11]+2x+1

=x^3*[(√3 -2)*(1-√3)+11]+2x+1

=x^3*[(√3 -2)*(1-√3)+11]+2x+1

=x^3*[-5+3√3+11]+2x+1

=x^3*(6+3√3)+2x+1

=3x^3*(2+√3)+2x+1

=3*(√3 -2)*(√3 -2)*(√3 -2)*(√3+2)+2x+1

=-3*(√3 -2)*(√3 -2)+2*(√3 -2)+1

=-3*(7-4√3)+2√3 -3

=-24+14√3