sicp习题试解 (1.46)

王朝other·作者佚名  2006-01-09
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; ======================================================================

;

; Structure and Interpretation of Computer Programs

; (trial answer to excercises)

;

; 计算机程序的构造和解释(习题试解)

;

; created: code17 03/06/05

; modified:

; (保持内容完整不变前提下,可以任意转载)

; ======================================================================

;; SICP No.1.46

(define (iterative-improve good-enough? improve)

(define (try-it x)

(if (good-enough? x) x (try-it (improve x))))

(lambda (x) (try-it x)))

;; sqrt,采用1-1-7节中原来的good-enough?和improve函数定义

(define (sqrt x)

(define (good-enough? guess)

(< (abs (- (square guess) x)) 0.001))

(define (improve guess)

(average guess (/ x guess)))

((iterative-improve good-enough? improve) 1.0))

;; fixed-point

(define (fixed-point f first-guess)

(define tolerance 0.00001)

(define (good-enough? guess)

(< (abs (- guess (f guess))) tolerance))

(define (improve guess) (f guess))

((iterative-improve good-enough? improve) first-guess))

;; Test-it

;; Welcome to MzScheme version 209, Copyright (c) 2004 PLT Scheme, Inc.

;; ;; 新的sqrt的测试结果与课本中原始版本的结果完全一致

;; > (sqrt 9)

;; 3.00009155413138

;; > (sqrt (+ (sqrt 2) (sqrt 3)))

;; 1.7739279023207892

;; > (square (sqrt 1000))

;; 1000.000369924366

;;

;; ;; 新的fixed-point的测试结果与课本中原始版本非常接近,但不完全一致。原因是

;; ;; 课本中采用的close-enough?函数取guess 和(f guess)两个参数,如果满足条

;; ;; 件,主函数取(f guess)为最后结果;而在使用iterative-improve模式时,

;; ;; 按照一般形式,good-enough?只能取一个参数,那么只能是guess,通过判断

;; ;; guess满足条件(guess与(f guess)差值小于tolerance),iterative-improve

;; ;; 的定义是取guess为最后结果而不是(f guess)。这是造成微小数值的差异的原因。

;; > (fixed-point cos 1.0)

;; 0.7390893414033927

;; > (fixed-point (lambda (y) (+ (sin y) (cos y))) 1.0)

;; 1.2587228743052672

;; >

 
 
 
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