<%
Function EnPas(CodeStr)
Dim CodeLen
Dim CodeSpace
Dim NewCode
CodeLen = 30
CodeSpace = CodeLen - Len(CodeStr)
If Not CodeSpace < 1 Then
For cecr = 1 To CodeSpace
CodeStr = CodeStr & Chr(21)
Next
End If
NewCode = 1
Dim Been
For cecb = 1 To CodeLen
Been = CodeLen + Asc(Mid(CodeStr,cecb,1)) * cecb
NewCode = NewCode * Been
Next
CodeStr = NewCode
NewCode = Empty
For cec = 1 To Len(CodeStr)
NewCode = NewCode & CfsCode(Mid(CodeStr,cec,3))
Next
For cec = 20 To Len(NewCode) - 18 Step 2
EnPas = EnPas & Mid(NewCode,cec,1)
Next
End Function
Function CfsCode(Word)
For cc = 1 To Len(Word)
CfsCode = CfsCode & Asc(Mid(Word,cc,1))
Next
CfsCode = Hex(CfsCode)
End Function
%>
跪求答案！答对者给予500分！谢谢！
答案肯定是30位的字符串！否则肯定错！
參考答案:293740B3817A38ADC0898C1858AA86
你都有加密算法了，自己用VB写一个，或用ASP写一个，用IIS调试下就行了呀，怎么不知道呢。
