<?
if(!nick){//$nick为表单中传递过来的变量,需要留言者留下自己的name
$back = "<b><font size=5>Please enter your name . Go back and try again :)</font></b>";
echo $back;
exit;
}
谁能把这段程序和表单写在一个页上
參考答案:<html>
<head><title></title></head>
<body>
<?php
if(!isset($_POST['tj']))
{?>
<form action="" method="POST">
<input type=text name="nick">
<input type=submit name='tj' value="提交">
</form>
<?php
}else{
if(strlen(trim($_POST['nick']))=="")
{
$back="<b><font size=5>Please enter your name . Go back and try again :)</font></b>";
die("$back");
}
}
?>
</body>
</html>