(x+y)^2-4(x+y-1)
(x+y)(x+y-1)-2
12p^2+17p-5
(y^2+y-8)(y^2+y-6)-24
要过程,谢谢!!!!!!!!!!!!
參考答案:x+y)^2-4(x+y-1)
=(x+y)^2-4(x+y)+4
=(x+y-2)^2
(x+y)(x+y-1)-2
=(x+y)^2-(x+y)-2
=(x+y-2)(x+y+1)
12p^2+17p-5
=[4p-1][3p+5]
(y^2+y-8)(y^2+y-6)-24
=(y^2+y)^2-14(y^2+y)+48-24
=(y^2+y)^2-14(y^2+y)+24
=(y^2+y-2)(y^2+y-12)
=(y+2)(y-1)(y+4)(y-3)